2m^2+7m+6=4

Solution for 2m^2+7m+6=4 equation:

2m^2+7m+6=4

We move all terms to the left:

2m^2+7m+6-(4)=0

We add all the numbers together, and all the variables

2m^2+7m+2=0

a = 2; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·2·2
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{33}}{2*2}=\frac{-7-\sqrt{33}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{33}}{2*2}=\frac{-7+\sqrt{33}}{4}
$